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Avko	10.06.2020 20:34
Predmet:Re: SQL upiti Citiraj Gjoreski: jel datum uslov ili nije zapocne se od danasnjeg dana, a danasnji dan je recimo 1.6. sutra ce biti 2.6 itd. recimo da ce WHERE biti date>='$danasnjiDatum'

Gjoreski	10.06.2020 23:05
Predmet:Re: SQL upiti Opet se nerazumemo Pitajne glasi. 1. Ako je datum uslov od cega se sostoi on ? 1. Jedan datum 2. Moze biti vise datuma 2. id_Office je isto uslov - E sad ako je jedan datum onda imamo uslov r1.date >= DATE('2020-06-01') sta je ispravno ali ces dobiti podatke samo za tog datuma -- Ako je ovako dobicemo Sve radnike koi su radili u kancalarijama gde je radio Vasko bez razlika dali Vasko je bio na posao - Ako su vise datuma po koj kriterium ih biramo Dali su oni u nekakav raspon OD DO ili je uslov Vasko kad je radio Ako je u rasponu OD DO bobijamo isti rezultat kako i predhodno samo za odredzeni period Ako je uslov Vasko za dobijajne datuma onda je moje resejne od posta #31 ispravno Znaci u resejne #31 imamo uslov ON r1.date=tUs.date AND s1.id_office=tUs.id_office Evo sta jas dobijam
Prilozi: Vasko.png (Velicina datoteke:41.13 KB)

Gjoreski

10.06.2020 23:05

Predmet:Re: SQL upiti

Opet se nerazumemo
Pitajne glasi.
1. Ako je datum uslov od cega se sostoi on ? 1. Jedan datum
2. Moze biti vise datuma
2. id_Office je isto uslov
- E sad ako je jedan datum onda imamo uslov r1.date >= DATE('2020-06-01') sta je ispravno ali ces dobiti
podatke samo za tog datuma
-- Ako je ovako dobicemo Sve radnike koi su radili u kancalarijama gde je radio Vasko bez razlika dali
Vasko je bio na posao
- Ako su vise datuma po koj kriterium ih biramo
Dali su oni u nekakav raspon OD DO ili je uslov Vasko kad je radio
Ako je u rasponu OD DO bobijamo isti rezultat kako i predhodno samo za odredzeni period
Ako je uslov Vasko za dobijajne datuma onda je moje resejne od posta #31 ispravno
Znaci u resejne #31 imamo uslov ON r1.date=tUs.date AND s1.id_office=tUs.id_office

Evo sta jas dobijam

Prilozi:
Vasko.png (Velicina datoteke:41.13 KB)

Avko	10.06.2020 23:29
Predmet:Re: SQL upiti da to je tocno, ali kada pokrenem taj upit ja dobijem ovo: i nemogu sortirati po datumu

Avko

10.06.2020 23:29

Predmet:Re: SQL upiti

da to je tocno, ali kada pokrenem taj upit ja dobijem ovo:

i nemogu sortirati po datumu

Gjoreski	11.06.2020 00:10
Predmet:Re: SQL upiti PreuzmiIzvorni kôd (SQL): SELECT r1.DATE, e1.id_employees, r1.id_department, s1.id_office, s1.startTime,CONCAT(r1.id_department,'_',s1.id_office,'_',r1.DATE) AS Uslov FROM tbl_schedule AS r1 INNER JOIN tbl_calendar AS k1 ON r1.DATE = k1.DATE LEFT JOIN tbl_citydepartmentoffice AS s1 ON (k1.id_cityDepartmentOffice = s1.Id_cityDeparmentOffice AND r1.id_department = s1.id_department) INNER JOIN tbl_employees AS e1 ON r1.id_employees=e1.id_employees INNER JOIN ( SELECT ra1.DATE, ea1.id_employees, ra1.id_department, sa1.id_office, sa1.startTime FROM tbl_schedule AS ra1 INNER JOIN tbl_calendar AS ka1 ON ra1.DATE = ka1.DATE LEFT JOIN tbl_citydepartmentoffice AS sa1 ON (ka1.id_cityDepartmentOffice = sa1.Id_cityDeparmentOffice AND ra1.id_department = sa1.id_department) INNER JOIN tbl_employees AS ea1 ON ra1.id_employees=ea1.id_employees WHERE ea1.id_employees=1001) tUs ON CONCAT(s1.id_office,'_',r1.DATE) = CONCAT(tUs.id_office,'_',tUs.DATE) ORDER BY r1.DATE ASC, r1.id_department ASC;

Gjoreski

11.06.2020 00:10

Predmet:Re: SQL upiti

PreuzmiIzvorni kôd (SQL):

SELECT r1.DATE, e1.id_employees, r1.id_department, s1.id_office, s1.startTime,CONCAT(r1.id_department,'_',s1.id_office,'_',r1.DATE) AS Uslov
FROM tbl_schedule AS r1
INNER JOIN tbl_calendar AS k1 ON r1.DATE = k1.DATE
LEFT JOIN tbl_citydepartmentoffice AS s1 ON (k1.id_cityDepartmentOffice = s1.Id_cityDeparmentOffice AND r1.id_department = s1.id_department)
INNER JOIN tbl_employees AS e1 ON r1.id_employees=e1.id_employees
INNER JOIN (
SELECT ra1.DATE, ea1.id_employees, ra1.id_department, sa1.id_office, sa1.startTime
FROM tbl_schedule AS ra1
INNER JOIN tbl_calendar AS ka1 ON ra1.DATE = ka1.DATE
LEFT JOIN tbl_citydepartmentoffice AS sa1 ON (ka1.id_cityDepartmentOffice = sa1.Id_cityDeparmentOffice AND ra1.id_department = sa1.id_department)
INNER JOIN tbl_employees AS ea1 ON ra1.id_employees=ea1.id_employees
WHERE ea1.id_employees=1001) tUs
ON CONCAT(s1.id_office,'_',r1.DATE) = CONCAT(tUs.id_office,'_',tUs.DATE)
ORDER BY r1.DATE ASC, r1.id_department ASC;

Avko

11.06.2020 00:39

Predmet:Re: SQL upiti

@Gjoreski

date Ascending 1	id_employees	id_department	id_office	startTime	Uslov
2020-06-01	1001	10	1	05:00:00	10_1_2020-06-01
2020-06-01	1002	310	1	11:00:00	310_1_2020-06-01
2020-06-01	1003	610	1	17:00:00	610_1_2020-06-01
2020-06-02	1008	30	3	06:00:00	30_3_2020-06-02
2020-06-02	1009	330	3	12:00:00	330_3_2020-06-02
2020-06-02	1001	630	3	18:00:00	630_3_2020-06-02
2020-06-03	1009	30	3	06:00:00	30_3_2020-06-03
2020-06-03	1001	330	3	12:00:00	330_3_2020-06-03
2020-06-03	1002	630	3	18:00:00	630_3_2020-06-03
2020-06-04	1001	30	3	06:00:00	30_3_2020-06-04
2020-06-04	1002	330	3	12:00:00	330_3_2020-06-04
2020-06-04	1003	630	3	18:00:00	630_3_2020-06-04
2020-06-05	1008	20	2	05:30:00	20_2_2020-06-05
2020-06-05	1009	320	2	11:30:00	320_2_2020-06-05
2020-06-05	1001	620	2	17:30:00	620_2_2020-06-05
2020-06-06	1009	20	2	09:00:00	20_2_2020-06-06
2020-06-06	1001	320	2	15:00:00	320_2_2020-06-06

to je to ali fali joÅ¡ da napiÅ¡e i

2020-06-07

1001

Gjoreski	11.06.2020 16:34
Predmet:Re: SQL upiti PreuzmiIzvorni kôd (SQL): SELECT r1.DATE, e1.id_employees, r1.id_department, s1.id_office, s1.startTime,CONCAT(r1.id_department,'_',s1.id_office,'_',r1.DATE) AS Uslov FROM tbl_schedule AS r1 INNER JOIN tbl_calendar AS k1 ON r1.DATE = k1.DATE LEFT JOIN tbl_citydepartmentoffice AS s1 ON (k1.id_cityDepartmentOffice = s1.Id_cityDeparmentOffice AND r1.id_department = s1.id_department) INNER JOIN tbl_employees AS e1 ON r1.id_employees=e1.id_employees INNER JOIN ( SELECT ra1.DATE, ea1.id_employees, ra1.id_department, sa1.id_office, sa1.startTime FROM tbl_schedule AS ra1 INNER JOIN tbl_calendar AS ka1 ON ra1.DATE = ka1.DATE LEFT JOIN tbl_citydepartmentoffice AS sa1 ON (ka1.id_cityDepartmentOffice = sa1.Id_cityDeparmentOffice AND ra1.id_department = sa1.id_department) INNER JOIN tbl_employees AS ea1 ON ra1.id_employees=ea1.id_employees WHERE ea1.id_employees=1001) tUs ON CONCAT(s1.id_office,'_',r1.DATE) = CONCAT(tUs.id_office,'_',tUs.DATE) UNION ALL SELECT r1.DATE, e1.id_employees, r1.id_department, s1.id_office, s1.startTime,CONCAT(r1.id_department,'_',s1.id_office,'_',r1.DATE) AS Uslov FROM tbl_schedule AS r1 INNER JOIN tbl_calendar AS k1 ON r1.DATE = k1.DATE LEFT JOIN tbl_citydepartmentoffice AS s1 ON (k1.id_cityDepartmentOffice = s1.Id_cityDeparmentOffice AND r1.id_department = s1.id_department) INNER JOIN tbl_employees AS e1 ON r1.id_employees=e1.id_employees INNER JOIN ( SELECT ra1.DATE, ea1.id_employees, ra1.id_department, sa1.id_office, sa1.startTime FROM tbl_schedule AS ra1 INNER JOIN tbl_calendar AS ka1 ON ra1.DATE = ka1.DATE LEFT JOIN tbl_citydepartmentoffice AS sa1 ON (ka1.id_cityDepartmentOffice = sa1.Id_cityDeparmentOffice AND ra1.id_department = sa1.id_department) INNER JOIN tbl_employees AS ea1 ON ra1.id_employees=ea1.id_employees WHERE ea1.id_employees=1001) tUs ON r1.DATE=tUs.DATE AND e1.id_employees=tUs.id_employees WHERE ISNULL(s1.id_office) ORDER BY DATE ASC, id_department ASC

Gjoreski

11.06.2020 16:34

Predmet:Re: SQL upiti

PreuzmiIzvorni kôd (SQL):

SELECT r1.DATE, e1.id_employees, r1.id_department, s1.id_office, s1.startTime,CONCAT(r1.id_department,'_',s1.id_office,'_',r1.DATE) AS Uslov
FROM tbl_schedule AS r1
INNER JOIN tbl_calendar AS k1 ON r1.DATE = k1.DATE
LEFT JOIN tbl_citydepartmentoffice AS s1 ON (k1.id_cityDepartmentOffice = s1.Id_cityDeparmentOffice AND r1.id_department = s1.id_department)
INNER JOIN tbl_employees AS e1 ON r1.id_employees=e1.id_employees
INNER JOIN (
SELECT ra1.DATE, ea1.id_employees, ra1.id_department, sa1.id_office, sa1.startTime
FROM tbl_schedule AS ra1
INNER JOIN tbl_calendar AS ka1 ON ra1.DATE = ka1.DATE
LEFT JOIN tbl_citydepartmentoffice AS sa1 ON (ka1.id_cityDepartmentOffice = sa1.Id_cityDeparmentOffice AND ra1.id_department = sa1.id_department)
INNER JOIN tbl_employees AS ea1 ON ra1.id_employees=ea1.id_employees
WHERE ea1.id_employees=1001) tUs
ON CONCAT(s1.id_office,'_',r1.DATE) = CONCAT(tUs.id_office,'_',tUs.DATE)
UNION ALL
SELECT r1.DATE, e1.id_employees, r1.id_department, s1.id_office, s1.startTime,CONCAT(r1.id_department,'_',s1.id_office,'_',r1.DATE) AS Uslov
FROM tbl_schedule AS r1
INNER JOIN tbl_calendar AS k1 ON r1.DATE = k1.DATE
LEFT JOIN tbl_citydepartmentoffice AS s1 ON (k1.id_cityDepartmentOffice = s1.Id_cityDeparmentOffice AND r1.id_department = s1.id_department)
INNER JOIN tbl_employees AS e1 ON r1.id_employees=e1.id_employees
INNER JOIN (
SELECT ra1.DATE, ea1.id_employees, ra1.id_department, sa1.id_office, sa1.startTime
FROM tbl_schedule AS ra1
INNER JOIN tbl_calendar AS ka1 ON ra1.DATE = ka1.DATE
LEFT JOIN tbl_citydepartmentoffice AS sa1 ON (ka1.id_cityDepartmentOffice = sa1.Id_cityDeparmentOffice AND ra1.id_department = sa1.id_department)
INNER JOIN tbl_employees AS ea1 ON ra1.id_employees=ea1.id_employees
WHERE ea1.id_employees=1001) tUs
ON r1.DATE=tUs.DATE AND e1.id_employees=tUs.id_employees
WHERE ISNULL(s1.id_office)
ORDER BY DATE ASC, id_department ASC

Avko	12.06.2020 00:44
Predmet:Re: SQL upiti 1. nema 1001 za 1.6. 2. zasto mi u rezultatu daje EDIT, COPY, DELETE kolone? (mozda ovo LINK, greÅ¡ka u phpAdminu, koliko sam razumio)

Avko

12.06.2020 00:44

Predmet:Re: SQL upiti

1. nema 1001 za 1.6.
2. zasto mi u rezultatu daje EDIT, COPY, DELETE kolone? (mozda ovo LINK, greÅ¡ka u phpAdminu, koliko sam razumio)

Gjoreski	12.06.2020 10:01
Predmet:Re: SQL upiti Ja sam na sql a koi si potvrdio dodao jos jedan sql sa union za ono FD sta nije bilo . Smatram da je problem taj PHP myAdmin koj koristis,Potrazi uzmi neki alat za misajne koda u my sql i vidi sta ces dobiti. Za pocetak pokreni oba dva sql a bez Union All I pogledaj rezultat. Evo sta ja dobijam:
Prilozi: 1111.png (Velicina datoteke:51.23 KB)

Gjoreski

12.06.2020 10:01

Predmet:Re: SQL upiti

Ja sam na sql a koi si potvrdio dodao jos jedan sql sa union za ono FD sta nije bilo . Smatram da je problem taj PHP myAdmin koj koristis,Potrazi uzmi neki alat za misajne koda u my sql i vidi sta ces dobiti.
Za pocetak pokreni oba dva sql a bez Union All I pogledaj rezultat.
Evo sta ja dobijam:

Prilozi:
1111.png (Velicina datoteke:51.23 KB)

Avko

12.06.2020 23:08

Predmet:Re: SQL upiti

1. sql

PreuzmiIzvorni kôd (Text):

SELECT r1.date, e1.id_employees, r1.id_department, s1.id_office, s1.startTime,CONCAT(r1.id_department,'_',s1.id_office,'_',r1.date) AS Uslov
FROM tbl_schedule AS r1
INNER JOIN tbl_calendar AS k1 ON r1.date = k1.date
LEFT JOIN tbl_citydepartmentoffice AS s1 ON (k1.id_cityDepartmentOffice = s1.Id_cityDeparmentOffice AND r1.id_department = s1.id_department)
INNER JOIN tbl_employees AS e1 ON r1.id_employees=e1.id_employees
INNER JOIN (
SELECT ra1.date, ea1.id_employees, ra1.id_department, sa1.id_office, sa1.startTime
FROM tbl_schedule AS ra1
INNER JOIN tbl_calendar AS ka1 ON ra1.date = ka1.date
LEFT JOIN tbl_citydepartmentoffice AS sa1 ON (ka1.id_cityDepartmentOffice = sa1.Id_cityDeparmentOffice AND ra1.id_department = sa1.id_department)
INNER JOIN tbl_employees AS ea1 ON ra1.id_employees=ea1.id_employees
WHERE ea1.id_employees=1001) tUs
ON CONCAT(s1.id_office,'_',r1.date) = CONCAT(tUs.id_office,'_',tUs.date)

rezultat:

date	id_employees	id_department	id_office	startTime	Uslov
2020-06-01	1001	10	1	05:00:00	10_1_2020-06-01
2020-06-01	1002	310	1	11:00:00	310_1_2020-06-01
2020-06-01	1003	610	1	17:00:00	610_1_2020-06-01
2020-06-04	1001	30	3	06:00:00	30_3_2020-06-04
2020-06-04	1002	330	3	12:00:00	330_3_2020-06-04
2020-06-04	1003	630	3	18:00:00	630_3_2020-06-04
2020-06-03	1001	330	3	12:00:00	330_3_2020-06-03
2020-06-03	1002	630	3	18:00:00	630_3_2020-06-03
2020-06-03	1009	30	3	06:00:00	30_3_2020-06-03
2020-06-05	1001	620	2	17:30:00	620_2_2020-06-05
2020-06-05	1008	20	2	05:30:00	20_2_2020-06-05
2020-06-05	1009	320	2	11:30:00	320_2_2020-06-05
2020-06-02	1001	630	3	18:00:00	630_3_2020-06-02
2020-06-02	1008	30	3	06:00:00	30_3_2020-06-02
2020-06-02	1009	330	3	12:00:00	330_3_2020-06-02
2020-06-06	1001	320	2	15:00:00	320_2_2020-06-06
2020-06-06	1009	20	2	09:00:00	20_2_2020-06-06

2.sql

PreuzmiIzvorni kôd (Text):

SELECT r1.date, e1.id_employees, r1.id_department, s1.id_office, s1.startTime,CONCAT(r1.id_department,'_',s1.id_office,'_',r1.date) AS Uslov
FROM tbl_schedule AS r1
INNER JOIN tbl_calendar AS k1 ON r1.date = k1.date
LEFT JOIN tbl_citydepartmentoffice AS s1 ON (k1.id_cityDepartmentOffice = s1.Id_cityDeparmentOffice AND r1.id_department = s1.id_department)
INNER JOIN tbl_employees AS e1 ON r1.id_employees=e1.id_employees
INNER JOIN (
SELECT ra1.date, ea1.id_employees, ra1.id_department, sa1.id_office, sa1.startTime
FROM tbl_schedule AS ra1
INNER JOIN tbl_calendar AS ka1 ON ra1.date = ka1.date
LEFT JOIN tbl_citydepartmentoffice AS sa1 ON (ka1.id_cityDepartmentOffice = sa1.Id_cityDeparmentOffice AND ra1.id_department = sa1.id_department)
INNER JOIN tbl_employees AS ea1 ON ra1.id_employees=ea1.id_employees
WHERE ea1.id_employees=1001) tUs
ON r1.date=tUs.date AND e1.id_employees=tUs.id_employees
WHERE ISNULL(s1.id_office)
ORDER BY date ASC, id_department ASC

date	id_employees	id_department	id_office	startTime	Uslov
2020-06-07	1001	FD	NULL NULL NULL

to je to, hvala Gjoreski. Rezultat je ono sto sam trazio.
Potrazit cu rijesenje za union all i prouciti.

hvala jos jednom